x^2-12x+8=-40

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Solution for x^2-12x+8=-40 equation: 



x^2-12x+8=-40

We move all terms to the left:

x^2-12x+8-(-40)=0

We add all the numbers together, and all the variables

x^2-12x+48=0

a = 1; b = -12; c = +48;
Δ = b2-4ac
Δ = -122-4·1·48
Δ = -48
Delta is less than zero, so there is no solution for the equation

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